Technique reference and sources
Think of the final stage expected value as a cash offer already sitting in your back pocket. On the first roll, any outcome above that pocket cash is worth keeping and any outcome below it should be rejected. At exact equality both choices pay the same on average, so keep above, continue below, and break ties by convention (for even dice the hurdle is a half-integer, so ties never occur).
When this method fits
- You have a single optional reroll on a die or random payout.
- You need to price an option to reject a first offer in favor of a redraw.
- An interviewer asks for the fair market price of a die roll with one reroll.
- You want to quantify the value of optionality in sequential decisions.
- Find terminal expected value. Calculate the average of all possible outcomes on the final roll: V_2 = (1 + S) / 2.
- Establish stopping hurdle. Stop on roll 1 if X_1 > V_2; reroll if X_1 <= V_2.
- Calculate stopping probability and conditional mean. Count faces above the hurdle and find their arithmetic mean.
- Weight by probabilities. Compute V_1 = P(stop) * E[stop] + P(reroll) * V_2.
- d6: (5 * 6 + 4) / 8 = 34 / 8 = 4.25
- d4: (5 * 4 + 4) / 8 = 24 / 8 = 3
- d8: (5 * 8 + 4) / 8 = 44 / 8 = 5.5
- d6 adds 6 / 8 = 0.75: 3.5 + 0.75 = 4.25
- d8 adds 8 / 8 = 1.0: 4.5 + 1.0 = 5.5
- d20 adds 20 / 8 = 2.5: 10.5 + 2.5 = 13
Common traps
Keeping a 3 on the first roll of a d6 because 3 is close to average. Roll 2 averages 3.5, which is strictly higher than 3. Keeping a 3 surrenders 0.5 in expected value compared to rerolling.
Averaging the stopping values with all first-roll values rather than weighting by their respective probabilities. Always weight conditional payoffs by branch probabilities: EV = P(stop) * E[stop] + P(reroll) * V_2.
Assuming you can return to the first roll if the second roll is worse. The problem specifies that the second roll is final and supersedes the first roll. Once you reroll, the first roll is gone.
- Roll 2 has expected value (1 + 8) / 2 = 4.5
- On roll 1, stop if face > 4.5: keep {5, 6, 7, 8} with average (5 + 8) / 2 = 6.5
- Reroll {1, 2, 3, 4} with probability 4 / 8 = 0.5 and continuation value 4.5
- Expected game value: 0.5 * 6.5 + 0.5 * 4.5 = 3.25 + 2.25 = 5.5
Source notes
These explanations and questions are written for QuantArc. Links show the underlying mathematics and learning design.
Jane Street: Probability & Markets Trading Interview Guide
Interview preparation guide (page 9) testing optimal stopping and market making on a d6 with one optional reroll. Lesson examples and questions are original.
Brainstellar: Probability interview puzzles
Free step-by-step walkthroughs of classic probability interview puzzles by difficulty; companion practice. Lesson examples and questions are original.
IES: Organizing Instruction and Study to Improve Student Learning
Supports worked examples, retrieval, explanations and spaced study. Does not establish QuantArc's exact lesson length, mastery threshold or review intervals.